SOLUTION: 2r+3s=0 r+5=6s

Question 26291: 2r+3s=0 r+5=6s
Answer by Alwayscheerful(414) (Show Source): You can put this solution on YOUR website!

Solved by pluggable solver: Linear System solver (using determinant)

Solve:

Any system of equations:

has solution

(r=-1, s=0.666666666666667}

Solved by pluggable solver: SOLVE linear system by SUBSTITUTION

Solve:
We'll use substitution. After moving 3*s to the right, we get:
, or . Substitute that
into another equation:
and simplify: So, we know that s=0.666666666666667. Since , r=-1.

Answer: .

Hope this helps!
RELATED QUESTIONS
Solving Systems of Equations in Three Variables. 2r+s+t=14 -r+-3s+2s=-2 (answered by fastblue)

2r-(5-r) (answered by sofiyac)

r - s + 2t = -1 2r + 2s - t = 0 r + s = 5 2r + 2t = 4 (answered by Alan3354)

5r-s+t=-9 2r+2s-3t=5... (answered by Alan3354)

r(r-8)/(2r+6)<0 (answered by lwsshak3)

Solve... (answered by jsmallt9)

3r-2s=5 and... (answered by mananth)

-7r^6s^5(-r^6s^4-5r^3s^4) How do I begin this? Can someone show me step by step... (answered by mananth)

This is what I have so far before I got confused multiply (2r+3s)^2 1st step:... (answered by stanbon)