SOLUTION: an airplane flew for 4.23 hours with a 25.5km/h tail wind. the return flight against the same tail wind took 4.97 hours. find the speed of the plane in still air.

Question 252978: an airplane flew for 4.23 hours with a 25.5km/h tail wind. the return flight against the same tail wind took 4.97 hours. find the speed of the plane in still air.
Found 2 solutions by richwmiller, Greenfinch:
Answer by richwmiller(17219) (Show Source): You can put this solution on YOUR website!
rt=d
(x+25.5)*4.23=(x-25.5)*4.97
x= airplane in still air
x=317.027 kmh
Nothing difficult here
No square roots nor quadratic formulas
Just multiply, divide, add and subtract numbers
Just remember you want x on the left and all numbers on the right side.

Answer by Greenfinch(383) (Show Source): You can put this solution on YOUR website!
Speed of aircraft is X
On outward trip (X + 25.5) = 4.23/Distance
On inbound trip (X - 25.5) = 4.97/Distance
Equating the distances
Distance = (X + 25.5)/4.97 = (X - 25.5)/4.23
So 4.23(X + 25.5) = 4.97(X - 25.5)
4.23X + 107.865 = 4.97X - 126.735
234.6 = 0.74 X
X= 317.027 km/hr

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