SOLUTION: 3x+6 over 4x+12 DIVIDED BY x^2-4 over x+3

Question 252593: 3x+6 over 4x+12 DIVIDED BY x^2-4 over x+3
Found 2 solutions by drk, jim_thompson5910:
Answer by drk(1908) (Show Source): You can put this solution on YOUR website!
here is the original problem:
/
----
step 1 - factor everything you can and then flip the second fraction and change to multiplication. We get
*
---
step 2 - cancel what you can. We get

which is:
3 / (4x-8)
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!

Start with the given expression.

Multiply the first fraction by the reciprocal of the second fraction .

Factor to get .

Factor to get .

Factor to get .

Combine the fractions.

Highlight the common terms.

Cancel out the common terms.

Simplify.

Distribute.

So simplifies to .

In other words,

RELATED QUESTIONS
3x+6 over 4x+12 divided by x squared minus 4 over... (answered by jorel1380)
x^2-4x+4 over 3x-6 divided by... (answered by tommyt3rd)
4x-12 over x^2+3x-10 <--- divided by 2x^2-13x+21 over... (answered by mananth)
How do i do (x-2)^2 over 4x^2 - 16 divided by 21x over... (answered by stanbon)
Could you please help me with this problem simplify as much as possible {{{x^2-x-12 (answered by Cintchr)
7 divided by x over 16-3x over... (answered by jim_thompson5910)
simplify: x^2-3x over 2x^2-3x-5 / 4x-12 over... (answered by Nate,checkley71)
How do I solve xy^2 over x^2 divided by x over y^3 ? Ex. 3x over 5y divided by 21x... (answered by mananth)
How do I solve xy^2 over x^2y divided by x over y^3 ? Ex. 3x over 5y divided by 21x... (answered by Fombitz)