SOLUTION: Zach invests $4000, part of it at 10% annual interest and the rest at 12% annual interest. If he earned $460 in interest at the end of one year, how much did he invest at each rat

Question 25256: Zach invests $4000, part of it at 10% annual interest and the rest at 12% annual interest. If he earned $460 in interest at the end of one year, how much did he invest at each rate?
Answer by elima(1433) (Show Source): You can put this solution on YOUR website!
Let x be the amount invested at 10%;
SO we have;
.10x=amount invested at 10%
(4000-x).12=amount invested at 12%
So our equation would be;
.10x+(4000-x).12=460
Distribute the 12%;
.10x+480-.12x=460
Put like terms together so you can see them better;
.10x-.12x+480=460
-.02x+480=460;
subtract 480 from both sides;
-.02x=-20
Multiply each side by -.02;
x=1000
Now that we know what was invested at 10% we can subtract that from $4000 to get what was invested at 12%;
$4000-$1000=$3000
Hope you understand
=)

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