SOLUTION: ten liters of 4% acid solution must be mixed with a 10% solution to get a 6% solution. How many liters of the 10% solution are needed?
Algebra.Com
Question 246507: ten liters of 4% acid solution must be mixed with a 10% solution to get a 6% solution. How many liters of the 10% solution are needed?
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
.04*10+.10x=.06(10+x)
.4+.10x=.6+.06x
.10x-.06x=.6-.4
.04x=.2
x=.2/.04
x=5 liters of 10% solution is used.
Proof:
.04*10+.10*5=.06(10+5)
.4+.5=.06*15
.9=.9
RELATED QUESTIONS
Ten liters of a 4% acid solution must be mixed with a 10% solution to get a 6% solution.... (answered by josmiceli)
Ten liters of a 4% acid solution must be mixed with a 10% solution to get a 6% solution.... (answered by nerdybill)
Ten liters of a 4% acid solution must be mixed with a 10% solution to get a 6% solution. (answered by Boreal)
ten liters of a 4% acid soluttion must be mixed with a 10% solution to get a 6% solution (answered by Paul)
5 liters of a 4 % solution must be mixed with a 10% solution to get a 6% solution. How... (answered by drk)
How many liters of 40% acid solution must be mixed with 10 liters of a 65% acid solution... (answered by josgarithmetic)
How many liters of a 4% solution of sulphuric acid must be mixed with how many liters of... (answered by ewatrrr)
How many liters of 7% acid must be mixed with how many liters of 12% acid solution by a... (answered by scott8148,Alan3354)
FIVE liters of a 4% solution must be mixed with a 10% sloution to get a 6%solution. how... (answered by fractalier)