SOLUTION: Systems of Equations
X+Y=16
2Y=-2X+2
please and thanks
Algebra.Com
Question 23966: Systems of Equations
X+Y=16
2Y=-2X+2
please and thanks
Answer by rapaljer(4671) (Show Source): You can put this solution on YOUR website!
For the second equation, add _2x to each side to get the equations in standard form:
x+y= 16
2x + 2y = 2
Multiply both sides of the first equation by -2 in order to eliminate the x coefficients, which by the way will also eliminate the y coefficients:
-2(x+y)= -2*16
2x + 2y = *2
-2x-2y = -32
2+2y= 2
0=-30
NO SOLUTION! Therefore the lines are parallel!!
R^2 at SCC
RELATED QUESTIONS
Systems of Linear Equations : Solve Algebraically
2x^2+y^2=17... (answered by checkley79)
Please help me solve these systems of equations using any algebra:
{{{x^2 + y = 8 }}}
(answered by MathLover1)
x+y+z=11
2x+3y++2z=27
x+2y+2z=19
Please show work solving the systems of... (answered by ewatrrr)
The systems of equations -2x=4-y 8-2y=x is a what type of system please help me and thank (answered by ReadingBoosters)
Please help me solve and graph the following systems of inequalities:
1. 2x+4y>16
(answered by pat6686)
Systems of Equations in three variables
x-4y+3z=-27
2x+2y-3z=22... (answered by Fombitz)
To solve systems of equations by the substitution method. Please help my son to solve... (answered by stanbon)
Solve the following systems of equations:
2x - 2y - 2z = -2
-x + y + 3z = 0
-3x +... (answered by stanbon)
solve the following systems of equations.
x+2y=3... (answered by persian52)