SOLUTION: Need help with this symbol manipulation problem please. S=2B+Ph Solve for h. My try: 2B/Ph h=2B?

Question 202755: Need help with this symbol manipulation problem please.
S=2B+Ph
Solve for h.
My try: 2B/Ph
h=2B?
Found 2 solutions by jsmallt9, PRMath:
Answer by jsmallt9(3758) (Show Source): You can put this solution on YOUR website!
S=2B+Ph
Solve for h

When you see the phrase: "solve for " it means "use Algebra to manipulate the equation until the variable is by itself on one side of the equation.

In you problem it means: Manipulate S=2B+Ph until h is by itself. In other words we want the equation to look like:
h = [some-expression]
or
[some-expression] = h
Since the h is already on the right side we will aim for:
[some-expression] = h

To get the h by itself we need to make the 2B and the P disappear, using proper Algebra

We'll start by subtracting 2B from both sides:
S - 2B = 2B + Ph - 2B
The 2B's on the right cancel giving:
S - 2B = Ph
We've made the "2B" disappear" from the right side! Now we will do the same with the "P". We can't, however, subtract "P" because "P" and "Ph" are not like terms! We can divide both sides by "P":

On the right side the P's cancel:

Guess what? We're done! We have "h" by itself so we have "solved for h".
Answer by PRMath(133) (Show Source): You can put this solution on YOUR website!
Need help with this symbol manipulation problem please.
S=2B+Ph
Solve for h.
My try: 2B/Ph
h=2B?

Close. You sort of lost track of your "S" variable. Keep thinking: "How can I isolate the "h"?"

So, here's the problem.......

S = 2B+ Ph You have a +2B so let's subtract it from both sides......

Now you have:

S - 2B = Ph Now how do we isolate the "h"? Well, you are multiplying between the P and the h. Sooooo, to sort of "get rid" of the P, you have to figure out how to "un-do" the multiplying between the P and the h. What is the OPPOSITE of multiplying? Try DIVIDING.

S-2B/P = h

Does this make sense to you? I hope so....
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