# SOLUTION: Please help me solve this problem: y=1/2x-3 y=1/3x+2 I tried this y=1/3x+2 -1/3x+y=2 -y=-y -1/3x =-y+2 3/1(-1/3x)=(-y+2)3/1 x=-3y+6 Then substitue

Algebra ->  Algebra  -> Expressions-with-variables -> SOLUTION: Please help me solve this problem: y=1/2x-3 y=1/3x+2 I tried this y=1/3x+2 -1/3x+y=2 -y=-y -1/3x =-y+2 3/1(-1/3x)=(-y+2)3/1 x=-3y+6 Then substitue       Log On

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 Question 201421: Please help me solve this problem: y=1/2x-3 y=1/3x+2 I tried this y=1/3x+2 -1/3x+y=2 -y=-y -1/3x =-y+2 3/1(-1/3x)=(-y+2)3/1 x=-3y+6 Then substitue x=-3y+6 y=1/x(-3y+6)-3 y=-3/xy+6/2-3 y=-3/2y+3-3 But now I am lostAnswer by stanbon(57984)   (Show Source): You can put this solution on YOUR website!y=1/2x-3 y=1/3x+2 ------------ Substitute to get: (1/2)x - 3 = (1/3)x + 2 [(1/2)-(1/3)]x = 5 (1/6)x = 5 x = 30 ----------- y = (1/2)30 - 3 y = 12 ====================== Cheers, Stan H.