SOLUTION: Find the perfect square trinomial whose first two terms are: a^2 - 8a Solve by completing the square. t^2 - 3t - 7 = 0 An object in launched directly upward at 64 feet per

Question 201101: Find the perfect square trinomial whose first two terms are:
a^2 - 8a
Solve by completing the square.
t^2 - 3t - 7 = 0
An object in launched directly upward at 64 feet per second (ft/s) from a platform 80 feet
high. What will be the object's maximum height? When will it attain this height?

Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
1) To find the perfect square trinomial, add the square of half the x-coefficient .
Simplify.

2) Solve by completing the square:
Add 7 to both sides.
Now complete the square in t by adding the square of half the t-coefficient to both sides. This is .
Factor the left side and simplify the right side.

Take the square root of both sides.
or Add to both sides of each solution.
or
3) Use the formula for the height of an object propelled upward with an initial velocity of ft/sec from an initial height of feet. AMP Parsing Error of [G = 32 ft/(sec)^2]: Invalid function ')^2': opening bracket expected at /home/ichudov/project_locations/algebra.com/templates/Algebra/Expression.pm line 70. . :
Substitute and
First find the time t at which the object reaches its maximum height. Remember that this equation, when graphed, will show a parabola that opens downward so that the vertex of the graph will be the maximum point of the curve or the time of maximum height, t.
The vertex of this parabola is given by where a = -16 and b = 64, so...

seconds.
The object will attain its maximum height in 2 seconds. To find the maximum height of the object, subtitute t = 2 into the beginning equation and solve for h.

feet is the maximum height attained by the object..
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