SOLUTION: Find a number such that four times two more than the number is the same seven less than the opposite of the number.

SOLUTION: Find a number such that four times two more than the number is the same seven less than the opposite of the number.

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Question 200808: Find a number such that four times two more than the number is the same seven less than the opposite of the number.
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Let n = the required number, then:
4(n+2) = -n-7
4n+8 = -n-7 Add n to both sides.
5n+8 = -7 Subtract 8 from both sides.
5n = -15 Divide both sides by 5.
n = -3
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