SOLUTION: Please help me...Find to the nearest degree, all values of x in the interval 0<x<180 that satisfy
the equation 8co
Algebra.Com
Question 197737: Please help me...Find to the nearest degree, all values of x in the interval 0
the equation 8cos^2x-2cosx - 1= 0. Thanks so much!
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Find to the nearest degree, all values of x in the interval 0
the equation 8cos^2x-2cosx - 1= 0
---------------------
Factor:
(4cos(x)+1)(2cos(x)-1) = 0
cos(x) = -1/4 or cos(x) = 1/2
x = 104.48 degrees or x = -104.48 degrees
or
x = 60 degrees or x = -60 degrees
=====================================================
Cheers,
Stan H.
RELATED QUESTIONS
Find to the nearest degree all values of theta in the interval 0 degrees is less than or... (answered by stanbon)
Find to the nearest degree, all values of X in the interval 0°≤X≤360° which... (answered by lwsshak3)
Find to the nearest tenth of a degree ,all values of x in the interval 0 less than/equal... (answered by Gogonati)
7cos theta + 1 = 6sec theta
Find, to the nearest degree, all values of theta in the... (answered by lwsshak3)
I need help figuring out this trigonometry problem.
Fin,d to the nearest degree, all... (answered by stanbon)
Find, to the nearest degree, all values of x in the interval 0° ≤ x ≤ 360°... (answered by Fombitz)
1)Find all real numbers that satisfy the equation: cos x = square root 3 / 2.
2)Solve... (answered by lynnlo)
Find all values of θ, to the nearest degree, that satisfy the equation 7cos... (answered by lwsshak3)
Find, to the nearest tenth of a degree, all values of x in the interval 0degree <_ x <... (answered by stanbon)