SOLUTION: I am homeschooled with the School of Tomorrow. I am currently doing Algebra 1, and am having a lot of touble with the section "Solving Simultaneous Equations Algebraically", lesson
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Question 197661: I am homeschooled with the School of Tomorrow. I am currently doing Algebra 1, and am having a lot of touble with the section "Solving Simultaneous Equations Algebraically", lesson "Substitution Method." The equation I am trying to work out now is:
Found 2 solutions by jim_thompson5910, checkley77:
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Start with the first equation.
Plug in into the first equation. In other words, replace each with . Notice we've eliminated the variables. So we now have a simple equation with one unknown.
Distribute
Combine like terms on the left side
Add 3 to both sides
Combine like terms on the right side
Divide both sides by 14.
Now that we know that , we can plug this into to find
Substitute for each
Multiply
Reduce
Combine like terms.
So our answers are and which form the ordered pair )
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
3x-4y=10
x=6y-1
now replace x in the first equation with(6y-1) & solve for y.
3(6y-1)-4y=10
18y-3-4y=10
14y=10+3
14y=13
y=13/14 ans.
x=6*13/14-1
x=78/14-1
x=(78-1*14)/14
x=(78-14)/14
x=64/14
x=32/7 ans.
Proof:
3*32/7-4*13/14=10
96/7-52/14=10
(96*2-52)/14=10
(192-52)/14=10
140/14=10
10=10
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