SOLUTION: Without drawing the graph of the equation, determine how many points the parabola has in common with the x-axis and whether its vertex lies above, on, or below the x-axis. y = 2x

Question 195270: Without drawing the graph of the equation, determine how many points the parabola has in common with the x-axis and whether its vertex lies above, on, or below the x-axis.
y = 2x^2 + x + 3

Answer by J2R2R(94) (Show Source): You can put this solution on YOUR website!
Without drawing the graph of the equation, determine how many points the parabola has in common with the x-axis and whether its vertex lies above, on, or below the x-axis.

y = 2x^2 + x + 3

Here, the discriminant will tell us how many real or imaginary roots we have.

b^2 � 4ac > 0 gives two real solutions which are different (crosses the x-axis in two places)

b^2 � 4ac = 0 gives two real solutions which are equal (crosses the x-axis in one place at the vertex)

b^2 � 4ac < 0 gives two complex solutions which are different (doesn�t cross the x-axis).

For our equation, a = 2, b = 1, c = 3

b^2 � 4ac = 1 � 24 = � 23

Thus we have two complex roots which are different and therefore the parabola doesn�t cross the x-axis so there are no points in common with the x-axis, and the vertex lies above the x-axis.
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