SOLUTION: 13+a=25+b
b-a= ?
Algebra.Com
Question 191891: 13+a=25+b
b-a= ?
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
Isolate "b-a" to one side of the equation.
.
If you started with:
13+a=25+b
Subtract 'a' from both sides:
13 = 25+b-a
Now, subtract 25 from both sides:
13-25 = b-a
-12 = b-a (this is what they're looking for)
RELATED QUESTIONS
a=3
b=13... (answered by carter6949)
A=12, B=_____ C=... (answered by ravenrinas)
Solve |b-7|< 6
a. 1>b>13
b. b>1
c. 1< b<13 (answered by math_tutor2020)
Which expression is equal to 5/sqrt13
a.)5sqrt15/13
b.)sqrt5/13
c.)25/13... (answered by greenestamps)
a^3 - b^2 = 11
a^2 + b =... (answered by MathLover1)
C = 13
B = 12
What does A... (answered by josgarithmetic,ikleyn)
aČ+bČ=25... (answered by KMST)
If a and b are prime numbers which if the following cannot be the sum of a and b?
A)13... (answered by ikleyn)
How to factor this equation... (answered by stanbon)