SOLUTION: # 7. A small area in front of a building is triangular in shape. The perimeter of the triangle is 49 meters. The second side is one-fourth of the first side in length. The third s

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Question 190615: # 7. A small area in front of a building is triangular in shape. The perimeter of the triangle is 49 meters. The second side is one-fourth of the first side in length. The third side is 4 meters more than the first side. Find the length in meters of each side of the triangular region

Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!
# 7
Q: A small area in front of a building is triangular in shape. The perimeter of the triangle is 49 meters. The second side is one-fourth of the first side in length. The third side is 4 meters more than the first side. Find the length in meters of each side of the triangular region

A:


Let
x = length of first side
y = length of second side
z = length of third side


Since "The second side is one-fourth of the first side in length", this means that

Also, since "The third side is 4 meters more than the first side", this means

Finally, because "The perimeter of the triangle is 49 meters", this tells us that


Start with the third equation.


Plug in and


Multiply EVERY term by the LCD to clear the fraction.


Distribute and multiply.


Combine like terms on the left side.


Subtract from both sides.


Combine like terms on the right side.


Divide both sides by to isolate .


Reduce.


So the length of the first side is 20 meters.


----------------------------------------------


Go back to the first equation


Plug in


Multiply


Reduce


So the length of the second side is 5 meters.

----------------------------------------------

Move onto the second equation


Plug in


Add


So the third side is 24 meters long.


=======================================================
Answer:


So the lengths of the three sides are:

First: 20 meters
Second: 5 meters
Third: 24 meters

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