SOLUTION: solving systems of linear equations.solve by substitution
2x+y=10
3x-4y=26
y=2x+3
3x+2y=6
solving systems of linear equations.solve by addition elimination
3x-6y=5
2
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Question 188887: solving systems of linear equations.solve by substitution
2x+y=10
3x-4y=26
y=2x+3
3x+2y=6
solving systems of linear equations.solve by addition elimination
3x-6y=5
2x-4y=8
Answer by jojo14344(1513) (Show Source): You can put this solution on YOUR website!
Solving systems of linear equations.Solve by substitution
2x+y=10, EQN 1
3x-4y=26, EQN 2
In EQN 1 we get, --> EQN 3, substitute in EQN 2
---->
, substitute in EQN 3:
Intersect at point (6,-2)
--->RED, EQN1; GREEN, EQN 2
y=2x+3, EQN 1
3x+2y=6, EQN 2
Substitute EQN 1 in EQN 2:
----> , subst. in EQN 1
---->
Intersect at point (0,3)
---> RED, EQN 1; GREEN, EQN 2
Solving systems of linear equations. Solve by addition elimination
3x-6y=5, EQN 1
2x-4y=8, EQN 2
Multiply EQN 1 by -4, EQN 2 by 6, and then "add":
x ---->
x ----->
no solution. These lines don't intersect:
We'll look for the intercepts:
In EQN 1, let fy=0
--->
let fx=0
--->
In EQN 2, let Fy=0
--->
Let fx=0
--->
---> RED, EQN 1; GREEN, EQN 2
Since they line on the same plane they are parallel
Thank you,
Jojo
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