SOLUTION: Solve the system of equations by substitution. 3y-4x=-1 y-5x=-15 I worked it out to (4,5). Am I right?

Question 181211This question is from textbook saxon algebra 2
: Solve the system of equations by substitution.
3y-4x=-1
y-5x=-15
I worked it out to (4,5). Am I right? This question is from textbook saxon algebra 2

Found 2 solutions by Alan3354, HyperBrain:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Solve the system of equations by substitution.
3y-4x=-1
y-5x=-15 --> y = 5x-15
I worked it out to (4,5). Am I right?
---------------
3(5x-15) - 4x = -1
15x-45 - 4x = -1
11x = 44
x = 4
------------
y = 5x-15
y = 5
You're close.
Answer by HyperBrain(694) (Show Source): You can put this solution on YOUR website!
(1)3y-4x=-1
(2)y-5x=-15
**
From (2), y=5x-15. Substituting this to (1) we have.
3(5x-15)-4x=-1
(15x-45)-4x=-1
11x-45=-1
11x=44
x=4
y=5x-15=5(4)-15=20-15=5
Therefore, the solution set is {(4,5)} Thus you are correct.
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