SOLUTION: can you please help me solve the following: (((How many x-intercepts the parabola has and wheather its vertex lies above or below or on the x-axis, y=x^2-5x+6)))

Question 180347This question is from textbook algebra structure and method
: can you please help me solve the following: (((How many x-intercepts the parabola has and wheather its vertex lies above or below or on the x-axis, y=x^2-5x+6))) This question is from textbook algebra structure and method

Answer by Mathtut(3670) (Show Source): You can put this solution on YOUR website!
set y = to zero when trying to find the x intercepts
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x=2 and 3
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since this has two intercepts we know that the vertex is NOT on the x axis
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we also know that this parabola opens up(coefficent is positive in x squared term) therefore we know the vertex is below the x axis, but not by much because the x intercepts are very close to each other
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we can find the exact vertex by completing the square
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so the vertex is at (5/2,-1/4)
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