SOLUTION: find three consecutive intergers such that the sum of twice the first and 4 times the second is equal to 20 more than twice the third

SOLUTION: find three consecutive intergers such that the sum of twice the first and 4 times the second is equal to 20 more than twice the third

Algebra.Com

Question 179558: find three consecutive intergers such that the sum of twice the first and 4 times the second is equal to 20 more than twice the third
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
LET X, X+1 & X+2 BE THE THREE CONSECUTIVE INTEGERS.
2X+4(X+1)=2(X+2)+20
2X+4X+4=2X+4+20
6X-2X=24-4
4X=20
X=20/4
X=5 FOR THE SMALLER INTEGER.
5+1=6 FOR THE MIDDLE INTEGER.
5+2=7 FOR THE LARGEST INTEGER.
PROOF:
2*5+4*6=2*7+20
10+24=14+20
34=34
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