SOLUTION: x^2+18x+14=(x+a)^2+b where a and b are numbers, then, a=? b=?

Question 179112: x^2+18x+14=(x+a)^2+b
where a and b are numbers, then, a=? b=?
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!

Clearly,

and

Since we know that

we can substitute this value into:

John

RELATED QUESTIONS
if x and y are prime numbers then which one of the following cannot equal x-y? A. 1 B.... (answered by Alan3354)

Given that a and b are both positive numbers solve 1)x^2+a^2/x^2+b^2>or equal to 0 (answered by stanbon)

please help. Write the expression 9x^2-9x+1 in the form a(x+b)^2+c, where a, b and c... (answered by AnlytcPhil)

Write the expression {{{9x^2-9x+1}}} in the form of {{{a(x+b)^2+c}}}. where a, b and... (answered by Fombitz,Alan3354)

Given {{{f(x) = x(1-ln x)}}}. Let a, b be any positive numbers where a is not equal to b, (answered by CPhill)

if ax�+bx+c=0, where a, b, and c are integers 
and its two solutions have to be... (answered by AnlytcPhil)
I need help with Part A and Part B!!
a) If 7 ^ x = 43 , then x =         
(b) If 14 ^ (  (answered by LinnW)
Write x^2-6x+7=0 in the form (x-a)^2=b! where a and b are... (answered by AnlytcPhil)
Let x = 2012(a - b), y = 2012(b - c), and z = 2012(c - a), where a,b,c are real numbers,... (answered by Edwin McCravy,ikleyn)