SOLUTION: What values of x are excluded for the function f(x) = (x-1)/(x^2+1)?
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Question 178169: What values of x are excluded for the function f(x) = (x-1)/(x^2+1)?
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
The values of x that are excluded are any values that would cause the denominator to be zero.
So take the denominator of  = {(x-1) \over (x^2+1)})
and set it equal to zero:
which has no solutions over the real numbers. Hence, the domain of f is 
Compare with  = {(x-1) \over (x^2-1)})
Here setting the denominator equal to zero yields:
which has two real solutions, namely 1 and -1. Therefore the the domain of g is 
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