SOLUTION: Okay, this is just part of an equation involving fractions that i am doing, but i was wondering,can you factor u^2+u^2v^2+v^2 into two binomials? Thats all i really need for the pr

Algebra ->  Expressions-with-variables -> SOLUTION: Okay, this is just part of an equation involving fractions that i am doing, but i was wondering,can you factor u^2+u^2v^2+v^2 into two binomials? Thats all i really need for the pr      Log On


   



Question 173986: Okay, this is just part of an equation involving fractions that i am doing, but i was wondering,can you factor u^2+u^2v^2+v^2 into two binomials? Thats all i really need for the problem.
thank you :)

Answer by jim_thompson5910(35256) About Me  (Show Source):
You can put this solution on YOUR website!

Looking at u%5E2%2Bu%5E2v%5E2%2Bv%5E2 we can see that the first term is u%5E2 and the last term is v%5E2 where the coefficients are 1 and 1 respectively.

Now multiply the first coefficient 1 and the last coefficient 1 to get 1. Now what two numbers multiply to 1 and add to the middle coefficient 1? Let's list all of the factors of 1:



Factors of 1:
1

-1 ...List the negative factors as well. This will allow us to find all possible combinations

These factors pair up and multiply to 1
1*1
(-1)*(-1)

note: remember two negative numbers multiplied together make a positive number


Now which of these pairs add to 1? Lets make a table of all of the pairs of factors we multiplied and see which two numbers add to 1

First NumberSecond NumberSum
111+1=2
-1-1-1+(-1)=-2


None of these pairs of factors add to 1. So the expression u%5E2%2Bu%5E2v%5E2%2Bv%5E2 cannot be factored