SOLUTION: Ok so I've tried to do this problem quite a few times and I just can't seem to get it. 2x+5y=19 x=32-7y I tried to solve by substitution, I did this: 2(32-7y)+5y=19 64-14y+5y=

Algebra.Com
Question 173903: Ok so I've tried to do this problem quite a few times and I just can't seem to get it.
2x+5y=19
x=32-7y
I tried to solve by substitution, I did this:
2(32-7y)+5y=19
64-14y+5y=19
20y=83
But as you can see that is not right, I cannot figure out what I am doing wrong. I am supposed to end up with an ordered pair, I just don't get it.

Found 2 solutions by stanbon, solver91311:
Answer by stanbon(75887)   (Show Source): You can put this solution on YOUR website!
2x+5y=19
x=32-7y
I tried to solve by substitution, I did this:
2(32-7y)+5y=19
64-14y+5y=19
-9y = -45
y = 5
---------
Substitute into x = 32-7y to get:
x = 32 - 7*5 = -3
============
Final Answer:
x = -3, y = 5
=================
Cheers,
Stan H.

Answer by solver91311(24713)   (Show Source): You can put this solution on YOUR website!
Your system:



Your solution:
Ok, spot on.
Still going well.
Oops! How did you manage to add to and come up with ? . Also, you subtracted 64 from the left side, but added it to the right side. You need to subtract 64 from both sides.









Half done. Now you need to go back and use this value for to calculate the value for that satisfies both equations.

So take and substitute for .



Now you can write your ordered pair because you have an value and a corresponding value.

The solution set for your system is (,).

Ah, ah, ah...not so fast. We still need to check the answers. Substituting the values of x and y into both equations must result in two true statements. Let's see:

True

True

Answer checks.

RELATED QUESTIONS

I have tried this so many times and I just cant seem to get it 0.6x+5 <... (answered by ptaylor)
Hi, I've tried solving this equation in multiple ways but can't seem to crack it. The... (answered by MathLover1,josgarithmetic,greenestamps)
Hello. I do not know if this fits into the right category but I tried my best. Ok so I... (answered by algebrapro18)
I ve tried to solve this problem several times and still not getting how it works. How do (answered by shree840)
ok ive tried to figure this out over and over and i just dont get it! how do u put a... (answered by longjonsilver)
Hello, I would like to find help in HOW to solve a quadratic equation such as the one... (answered by josgarithmetic,ikleyn)
I need a little help on my homework. I tried them all and I know some of them are right i (answered by greenestamps,jim_thompson5910,ikleyn)
I'd appreciate a response on this, tried to resolve a few times and couldn't get it... (answered by ikleyn)
ok here is my problem 6x+3=2x+11 now what do i do with it. ive tried everything and (answered by prabhjyot)