SOLUTION: The cashier in a movie box office sold 200 more adult admission tickets at $11.00 each than children admission tickets at $8.00 each. What is the minimum number of each type of tic

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Question 164690: The cashier in a movie box office sold 200 more adult admission tickets at $11.00 each than children admission tickets at $8.00 each. What is the minimum number of each type of ticket that the cashier can sell for the total receipts to be at least $5000.
Answer by mangopeeler07(462) About Me  (Show Source):
You can put this solution on YOUR website!
200 more adult admission tickets...than children admission tickets:

a=c+200

adults=$11 each
children=$8 each
total receipts=at least $5000


11a%2B8c%3E=5000


System:
a=c+200
11a%2B8c%3E=5000

Use substitution
11%28c%2B200%29%2B8c%3E=5000

Distribute
11c%2B2200%2B8c%3E=5000

Combine like terms
19c%2B2200%3E=5000

Subtract 2200 from both sides
19c%3E=2800

Divide both sides by 19
c%3E=148--------this is rounded up from 147.3, since you can't sell .3 of a ticket.

a=c+200
a=148+200
a=348

a%3E=348----since c might be more than 148.

Answer:
148 childrens tickets
348 adults tickets