SOLUTION: 7=6(2z=3)-5
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Question 157970This question is from textbook Algebra 1
: 7=6(2z=3)-5
This question is from textbook Algebra 1
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
ONE TOO MANY = SIGNS.
CORRECT & RESUBMIT.
UNLESS THE SECOND = SIGN (2Z=3) SHOULD BE A + SIGN THEN:
7=12Z+18-5
12Z=7-18+5
12Z=-6
Z=-6/12
Z=-1/5 OR -.5
PROOF:
7=12*-.5+18-5
7=-6+18-5
7=18-11
7=7
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