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put this solution on YOUR website!two jets are traveling towards each other and are 4000 km apart. The rate of one jet is 100 km/h faster than the rate of the other. if the jets pass each other after 2.5 hours, what is the rate of the faster jet?
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The relative speed of one jet to the other is (2v + 100) km/hr, and is equal to the distance over the time, 4000/2.5 = 1600
2v+100 = 1600
2v = 1500
v = 750
The faster jet moves at 750+100 = 850 km/hour.
