SOLUTION: z^2-64/z / z-8/z+5

Algebra.Com
Question 150628: z^2-64/z / z-8/z+5
Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!

Start with the given expression.


Multiply the first fraction by the reciprocal of the second fraction .


Factor to get .


Combine the fractions.


Highlight the common terms.


Cancel out the common terms.


Simplify.


So simplifies to .


In other words, where , , or

RELATED QUESTIONS

What is z-1/z-8 - z+1/z+8 + z-120/z^2-64... (answered by jim_thompson5910)
[(z^2 - 25) \ z] \ [(z - 5) \ (z -... (answered by jorel1380)
Please help. z^2-64/z divided by... (answered by jim_thompson5910)
Solve z^2+z=5 (answered by jim_thompson5910)
5(2-z)/4=-z (answered by jim_thompson5910)
Z (answered by Alan3354)
Please help solve. Factor completely 25s^2-121 Perform the indicated operations and... (answered by IridianGarcia)
z^2-64/8-z The simplified form is? I came up with Z^2-Z-8 is this... (answered by richwmiller)
z^2-64/8-z The simplified form is? I came up with Z^2-Z-8 is this... (answered by Alan3354)