SOLUTION: {{{-2k^0-4k+6(-k-2^0)-(-5k)=-(2-5)k-4k }}}
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Question 146104This question is from textbook Saxon Algebra 1
:
This question is from textbook Saxon Algebra 1
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
-2k^0-4k+6(-k-2^0)-(-5k)=-(2-5)k-4k
-2-4k-6k-6+5k=-(-3k)-4k Any number to ^0=1.
-5k-8=3k-4k
-5k-8=-k
-4k=8
k=-2
.
Ed
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