SOLUTION: 5a+24b=109.60
16a+24b=171
Have got this far. I understand how to write it in elimination.
Please show me how to write it correctly in substitution form
Algebra ->
Expressions-with-variables
-> SOLUTION: 5a+24b=109.60
16a+24b=171
Have got this far. I understand how to write it in elimination.
Please show me how to write it correctly in substitution form
Log On
Question 146071: 5a+24b=109.60
16a+24b=171
Have got this far. I understand how to write it in elimination.
Please show me how to write it correctly in substitution form Found 2 solutions by checkley77, edjones:Answer by checkley77(12844) (Show Source):
You can put this solution on YOUR website! 5a+24b=109.60
5a=109.6-24b
a=109.6/5-24b/5
now substitute (109.6/5-24b/5) for a in the other equation & solve for b.
16a+24b=171
16(109.6/5-24b/5)+24b=171
1753.6/5-384b/5+24b=171
-384b/5+24b=171-1753.6/5
(-384b+5*24b)/5=(5*171-1753.6)/5
(-384b+120b)/5=(855-1753.6)/5
264b/5=898.6/5 csncelling out the denominators we have:
264b=898.6
b=989.6/264 answer.
16a+24(898.6/264)=171
16a+21566.4/264=171
16a=171-21566.4/264
16a=(171*264-21566.4)/264
16a=(45144-21566.4)/264
16a=23577.6/264
a=(23577.6/264)(1/16)
a=23577.6/4224
a=61.4/11 answer.
Solve: We'll use substitution. After moving 24*b to the right, we get: , or . Substitute that
into another equation: and simplify: So, we know that b=3.40378787878788. Since , a=5.58181818181817.