SOLUTION: Factor Completely
252c^2+588cg+343g^2
Thank you I really need help with this!!!
Algebra.Com
Question 144590: Factor Completely
252c^2+588cg+343g^2
Thank you I really need help with this!!!
Found 2 solutions by checkley77, ankor@dixie-net.com:
Answer by checkley77(12844) (Show Source): You can put this solution on YOUR website!
252c^2+588cg+343g^2
7(36c^2+84cg+49g^2)
7(6c+7g)^2 answer.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Factor Completely
252c^2 + 588cg + 343g^2
:
Try a some low prime numbers to see if any will go evenly into all 3 numbers
Dividing each by 7 we get:
7(36c^2 + 84cg + 49g^2)
:
Note that the 1st and last coefficients are perfect squares, a clue that this may be factored to:
7(6c + 7g)(6c + 7g)
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