SOLUTION: 1/3x + 2/3 = y
5/7x - y - 2 = 0
This is supposed to be solved with substitution or elimination. Thanks.
Algebra.Com
Question 139468: 1/3x + 2/3 = y
5/7x - y - 2 = 0
This is supposed to be solved with substitution or elimination. Thanks.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
1/3x + 2/3 = y
5/7x - y - 2 = 0
This is supposed to be solved with substitution or elimination
---------------------
Multiply thru 1st equation by 3 ; Multiply thru 2nd equation by 7:
----------------------
x - y = -2
5x -7y = 14
------------------
Multiply the 1st equation by 5 to get:
5x - 5y = -10
5x - 7y = 14
---------------
Subtract 2nd equation from 1st to get;
2y = -24
y = -12
------------------
Substitute into x-y=-2 to solve for "x":
x--12 = -2
x +12 = -2
x = -14
----------------------
Check answer in 5x-7y = 14
5*-14 -7*-12 = 14
-70 + 84 = 14
14 = 14
------------------
Final Answer: x = -14 ; y = -12
====================================
Cheers,
Stan H.
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