SOLUTION: Hello, I have a few problems, and this should be easy but I'm over thinking it. f9x0 = x/x+t g(x)= x^3 A) Find f(x) + g(x) I found a common denominator, (x+1) but I got confu

Question 127634: Hello, I have a few problems, and this should be easy but I'm over thinking it.
f9x0 = x/x+t g(x)= x^3
A) Find f(x) + g(x)
I found a common denominator, (x+1) but I got confused after that...
x^3 is really X^3/1 so to get the common denominator, would you multiply by x since the one is already in the denominator or just by x? and what about the denominator?
Also, I have a function:
f(x)= cube root of (x-1) g(x)= x^3 + 1
c) f(f(x)=?
All you have to do is substitute for this problem, correct?
So... f(f(x))= {cube root[cube root of (x-1)] -1} Would be correct?

If anyone could set me straight with these, I'd appreciate it!
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!

Is the denominator or ? I'm going to assume a typo in the original function statement since you go on about .

The two denominators are and . Since they have no factors in common, the common denominator is the product of the two: ,

So:

is your answer...but you missed it by THAT much.

. See the difference? You just had a misplaced bracket.
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