SOLUTION: a a+b - + --- b a-b _______ a a-b - - --- b a+b In other terms: [(a/b)+(a+b)/(a/b)]/[(a/b)-(a-b)/(a+b)] I tried to multiply both denominator and numerator by [b(a+b)(

Question 126200: a a+b
- + ---
b a-b
_______
a a-b
- - ---
b a+b
In other terms:
[(a/b)+(a+b)/(a/b)]/[(a/b)-(a-b)/(a+b)]

I tried to multiply both denominator and numerator by [b(a+b)(a-b)}\] but that didnt seem to work for me.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
[(a/b)+(a+b)/(a-b)]/[(a/b)-(a-b)/(a+b)]
= {[a(a-b)+b(a+b)]/[b(a-b)]} / {[a(a+b)-b(a-b)]/[b(a+b)]
= {[a^2+b^2]/b(a-b)]} / {[a^2-b^2]/[b(a+b)]}
Invert the denominator and multiply after cancelling where you can:
= (a^2+b^2)
==================
Cheers,
Stan H.
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