SOLUTION: prove that a number and its cube leave the same remainder when divided by 6.

Algebra.Com
Question 124487:
prove that a number and its cube leave the same remainder when divided by 6.

Answer by checkley71(8403)   (Show Source): You can put this solution on YOUR website!
USING THE NUMBER 7.
WE HAVE 7/6=1 & REMANDER=1
7^3=343
343/6=57 & REMAINDER=1.

RELATED QUESTIONS

show that a number and it's cube leaves the same remainder when divided by 6 (answered by richard1234)
A certain number leaves a remainder of 4 when divided by 5, a remainder of 5 when divided (answered by ikleyn,ankor@dixie-net.com)
Find all the natural numbers, which when divided by 7, leave the same number for the... (answered by ikleyn,Solver92311)
What is the least number that when divided by 7 has a remainder of 4, and when divided by (answered by robertb)
Find the smallest number that gives a remainder of 1 when divided by 4, a remainder of 2... (answered by richwmiller)
When a natural number n is divided by the numbers 95, 112, 214 and 231, they all leave... (answered by ikleyn,greenestamps)
Prove the well known result that the remainder on dividing a number by 9 is the same as... (answered by richard1234)
Two numbers P and Q such that when divided by 6 ,they leave remainder 4 and 5... (answered by ankor@dixie-net.com)
list all the two-digit numbers which leave a remainder of 6 and when 171 is divided by... (answered by Fombitz)