SOLUTION: Solve the following system of equations.
4x+3y=8
4x+6y=20
x=
y=
Algebra.Com
Question 1203931: Solve the following system of equations.
4x+3y=8
4x+6y=20
x=
y=
Answer by Theo(13342) (Show Source): You can put this solution on YOUR website!
4x + 3y = 8
4x + 6y = 20
ssubtract the first equation from the second to get:
3y = 12
solve for y to get y = 4
sreplace y with 4 in the first equation to get:
4x + 12 = 8
subtract 12 from both sides of the equation to get:
4x =-4
solve for x to get:
x = -1
your values of x and y should be x = -1 and y = 4
replace x and y with that in both equations to get:
-4 + 12 = 8
-4 + 24 = 10
both equations are true, confirming the values of x and y are good.
your solution is that x = -1 and y = 4
if you graph both equations, the intersection of the straight lines will be at (-1,4) as shown below.
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