Product of the means equals the product of the extremes:
5a = 2b and 7a = 3c
Dividing equals by equals:
Cross-multiply:
Make c and 15 the extremes, and 14 and b the means:
Edwin
I would solve this problem by a very different method from the similar ones used by the other two tutors; I have a particular dislike for that "product of the means equals product of the extremes" rule, since it introduces unneeded new vocabulary.
Given the ratio of a:b and the ratio of a:c, and needing to find the ratio c:b, I would rewrite the second ratio as c:a; then I would "eliminate the middle man" in the ratios c:a and a:b.
c:a = 7:3
a:b = 2:5
rewrite each ratio as an equivalent ratio using the same number for a in both:
c:a = 14:6
a:b = 6:15
Combine them into a ratio comparing all three numbers...