SOLUTION: Solve for y when x=10+4z/10.
a. 2x+y-z=2
I tried the following:
2(10+4z/10)+y-z=2
20+8z/20+y-z=2
20(20+8z/20+y-z=2)
20+8z+20y-20z=20
-14z+20-20=-20y
-14z=-20y
-14z/-
Algebra.Com
Question 1175535: Solve for y when x=10+4z/10.
a. 2x+y-z=2
I tried the following:
2(10+4z/10)+y-z=2
20+8z/20+y-z=2
20(20+8z/20+y-z=2)
20+8z+20y-20z=20
-14z+20-20=-20y
-14z=-20y
-14z/-20=y
7/10=y
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!
Solve for y .
a.
.....when
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