SOLUTION: A party rental company has chairs and tables for rent. The total cost to rent 5 chairs and 6 tables is 60$. The total cost to rent 3 chairs and 2 tables is $22. What is the cost to

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Question 1157996: A party rental company has chairs and tables for rent. The total cost to rent 5 chairs and 6 tables is 60$. The total cost to rent 3 chairs and 2 tables is $22. What is the cost to rent each chair and each table?
Found 3 solutions by josgarithmetic, mananth, greenestamps:
Answer by josgarithmetic(39620)   (Show Source):
You can put this solution on YOUR website!
c chair price
t table price

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Answer by mananth(16946)   (Show Source):
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let rent for chair be x and that of table by y
The total cost to rent 5 chairs and 6 tables is 60$.
5x+6y=60
The total cost to rent 3 chairs and 2 tables is $22.
3x+2y=22
Solve equations
5.00 x + 6.00 y = 60.00

3.00 x + 2.00 y = 22.00 .............2
Eliminate y
multiply (1)by 1.00
Multiply (2) by -3.00
5.00 x 6.00 y = 60.00
-9.00 x -6.00 y = -66.00
Add the two equations
-4.00 x = -6.00
/ -4.00
x = 1.50
plug value of x in (1)
5.00 x + 6.00 y = 60.00
7.50 + 6.00 y = 60.00
6.00 y = 52.50
y = 8.75
Ans x = $1.50 rent each chair
y = $8.75 rent each table

Answer by greenestamps(13200)   (Show Source):
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An informal solution, using basically the same calculations you might use if you solved the problem formally using elimination....

Consider a third rental which is 3 times the second one shown: 9 chairs and 6 tables for $66.
The difference between that and the first rental is 4 more chairs for $6 more.
So the rental cost for each chair is $6/4 = $1.50.
Plug that into any one of the three rentals to determine the rental cost for each table.