SOLUTION: Solve the system by Substitution: 3x + 3 = 5y 4x + 2y = -4

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Question 1155473: Solve the system by Substitution:
3x + 3 = 5y
4x + 2y = -4

Found 2 solutions by MathLover1, greenestamps:
Answer by MathLover1(20850)   (Show Source): You can put this solution on YOUR website!

......eq.1
......eq.2
-----------------------
start with
......eq.1, solve for
......substitute in eq.2

......eq.2,...solve for
........both sides multiply by





go to
......eq.1, substitute





solution:


intersection point is at: (,)




Answer by greenestamps(13209)   (Show Source): You can put this solution on YOUR website!


I would never solve a system of equations like this using substitution; elimination is far easier.

However, if I did solve it using substitution, I would not solve for y and get an expression involving fractions and then substitute in the other equation.

Remember that, using substitution, you don't need to solve for y or x -- you can solve for 3y, or 7x, or whatever is convenient.

So here is how I would solve this using substitution.

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Now substitute "6x+6" for "10y" in the second equation:






Then finish from there by any method you choose.


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