SOLUTION: Divide 15 into two parts such that when the larger is divided by 3 and the smaller is divided by 2 the quotients are equal

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Question 1152980: Divide 15 into two parts such that when the larger is divided by 3 and the smaller is divided by 2 the quotients are equal
Found 2 solutions by MathLover1, MathTherapy:
Answer by MathLover1(20849)   (Show Source): You can put this solution on YOUR website!

let larger part be and smaller part


.........eq.1
when the larger is divided by and the smaller is divided by the quotients are equal:
.......solve for
.......eq.2
from eq.1 and eq.2 we have
........solve for




then
.........eq.1


two parts are and

Answer by MathTherapy(10552)   (Show Source): You can put this solution on YOUR website!

Divide 15 into two parts such that when the larger is divided by 3 and the smaller is divided by 2 the quotients are equal 
Now that you've seen the LONG way to do this, let me show you the SHORT and EASY way.

Let the larger be L

Then the smaller is 15 - L

We then get: 

2L = 3(15 - L) ------ Cross-multiplying

2L = 45 - 3L

5L = 45

 

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