.
y = 2x - 2 (1)
-4x - y = 26 (2)
You are lucky !! They just expressed "y" via "x" in the first equation,
and all you need is to substitute this expression y = 2x-2 from the first equation to the second.
By doing it, you get from the second equation
-4x - (2x-2) = 26.
Simplify and find x
-4x - 2x + 2 = 26
-6x = 26 - 2
-6x = 24
x = = -4.
Now, when you just know x, substitute its value into equation (1). You will get
y = 2*(-4) - 2 = -8 - 2 = -10.
ANSWER. x= -4, y= -10.
Solved.
It is how the SUBSTITUTION method works in this case.
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My lessons in this site on solving systems of two linear equations in two unknowns (Algebra-I curriculum) are
- Solution of the linear system of two equations in two unknowns by the Substitution method
- Solution of the linear system of two equations in two unknowns by the Elimination method
- Solution of the linear system of two equations in two unknowns using determinant
- Geometric interpretation of the linear system of two equations in two unknowns
- Useful tricks when solving systems of 2 equations in 2 unknowns by the Substitution method
Also, you have this free of charge online textbook in ALGEBRA-I in this site
- ALGEBRA-I - YOUR ONLINE TEXTBOOK.
The referred lessons are the part of this online textbook under the topic "Systems of two linear equations in two unknowns".
Save the link to this online textbook together with its description
Free of charge online textbook in ALGEBRA-I
https://www.algebra.com/algebra/homework/quadratic/lessons/ALGEBRA-I-YOUR-ONLINE-TEXTBOOK.lesson
to your archive and use it when it is needed.