SOLUTION: 2x + y - 2z = -1 3x - 3y - z = 5 x - 2y + 3z = 6

Algebra.Com
Question 1146813: 2x + y - 2z = -1
3x - 3y - z = 5
x - 2y + 3z = 6

Found 2 solutions by josgarithmetic, Alan3354:
Answer by josgarithmetic(39617)   (Show Source): You can put this solution on YOUR website!
This was done without rechecking:
2  1  -1  -1
3  -3  -1 5
1 -2  3   6

0  5  -8  -13
0  3  -10 -13
1 -2  3   6
then switch rows

1  -2  3  6
0  5  -8 -13
0  3  -10 -13

1  -2  3  6
0  15 -24 -29
0  15 -50 -65

E3-E3-E2;
E2+8E3 and  E1-3E3

1 -2 0 3
0  5 0 -5
0  0 1  1

1 -2  0  3
0  1  0 -1
0 0  1  1

then E1=E1+2E2

1  0  0  1
0  1  0 -1
0  0  1  1



Answer by Alan3354(69443)   (Show Source): You can put this solution on YOUR website!
2x + y - 2z = -1
3x - 3y - z = 5
x - 2y + 3z = 6
===============
No question, no request.
Think about it.

RELATED QUESTIONS

2x+3y-2z=1 -x-y+2z=5... (answered by TigerAlgebra)
2x+3y-z=4 3x+2y+2z=6 4x-y+3z=5 solve in three... (answered by josmiceli)
2w-3x+4y+z=7 w-x+3y-5z=10 3w+x-2y-2z=6... (answered by Alan3354)
3x+3y+3z=12 2x+2y+2z=9... (answered by Alan3354)
2x-3y+2z=6 x+8y+3z=-31... (answered by ewatrrr,Fombitz)
solve each system x+y-z= -1 4x-3y+2z= 16... (answered by venugopalramana)
2x + 3z = 4 3y + 2z = 5 3x + 4y = −16 (x, y, z) = 2x +... (answered by Alan3354)
solve Linear sestems when w=1 w+2x+2y+z=-2 w+3x-2y-z=-6 -2w-x+3y+3z=6 w+4x+y+2z=-14 (answered by Fombitz)
x+y-2z=-1 2x-y+z=-6... (answered by Fermat)