SOLUTION: Suppose ABCD is a square with side length (x-1) cm. If the area of rectangle ABFE is (x^2+x-2)cm^2 then the length of FC in cm, is
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Question 1142743: Suppose ABCD is a square with side length (x-1) cm. If the area of rectangle ABFE is (x^2+x-2)cm^2 then the length of FC in cm, is
Answer by solver91311(24713) (Show Source): You can put this solution on YOUR website!
If the side length of ABCD is 
, then the area of ABCD is 
.
The difference in the area of rectangle ABFE and square ABCD is \ =\ 3x\ -\ 3)
, and this is the area of rectangle DCFE.
One side of rectangle DCFE, namely DC, must have length ,
so either side orthogonal to side DC, one of which is side CF, must have a measure of:
John
My calculator said it, I believe it, that settles it
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