SOLUTION: Fully factor 81(7a+3)^4 - 72(7a+3)^2 + 16

SOLUTION: Fully factor 81(7a+3)^4 - 72(7a+3)^2 + 16

Algebra.Com

Question 1134226: Fully factor 81(7a+3)^4 - 72(7a+3)^2 + 16
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Hint: the 2 outside terms are perfect squares.

RELATED QUESTIONS
Fully factor 81(7a+3)^4 - 72(7a+3)^2 + 16 I would like MathTherapy to solve my... (answered by Alan3354,greenestamps)

I need help factoring the two following expressions: {{{ 36(2a^2 - 3)^2 - 44(2a^2 - 3) - (answered by ikleyn)

3/4(7a+2)=10 (answered by mszlmb)

5a^4+7a^3+a^2 please... (answered by venugopalramana)

7a-3(2a-4) (answered by tommyt3rd)

8a-2(7a-3) (answered by ewatrrr)

(7a+3)+(-a-5)=-16 (answered by Zef,Mathtut)

(7a+3)+(-a-5)=-16 (answered by jim_thompson5910)

2(5a-2)+3(4-7a)=-25 (answered by BGluvsmath)