SOLUTION: Please help. Solve the following systems by substitution. 5x - 2y = -5 y - 5x = 3 Thanks JMS

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Question 112719: Please help.
Solve the following systems by substitution.
5x - 2y = -5
y - 5x = 3
Thanks
JMS
Found 2 solutions by jim_thompson5910, MathLover1:
Answer by jim_thompson5910(21685) About Me  (Show Source):
You can put this solution on YOUR website!
Solved by pluggable solver: Solving a linear system of equations by subsitution


Lets start with the given system of linear equations

5%2Ax-2%2Ay=-5
-5%2Ax%2B1%2Ay=3

Now in order to solve this system by using substitution, we need to solve (or isolate) one variable. I'm going to choose y.

Solve for y for the first equation

-2%2Ay=-5-5%2AxSubtract 5%2Ax from both sides

y=%28-5-5%2Ax%29%2F-2 Divide both sides by -2.


Which breaks down and reduces to



y=5%2F2%2B%285%2F2%29%2Ax Now we've fully isolated y

Since y equals 5%2F2%2B%285%2F2%29%2Ax we can substitute the expression 5%2F2%2B%285%2F2%29%2Ax into y of the 2nd equation. This will eliminate y so we can solve for x.


-5%2Ax%2B1%2Ahighlight%28%285%2F2%2B%285%2F2%29%2Ax%29%29=3 Replace y with 5%2F2%2B%285%2F2%29%2Ax. Since this eliminates y, we can now solve for x.

-5%2Ax%2B1%2A%285%2F2%29%2B1%285%2F2%29x=3 Distribute 1 to 5%2F2%2B%285%2F2%29%2Ax

-5%2Ax%2B5%2F2%2B%285%2F2%29%2Ax=3 Multiply



-5%2Ax%2B5%2F2%2B%285%2F2%29%2Ax=3 Reduce any fractions

-5%2Ax%2B%285%2F2%29%2Ax=3-5%2F2 Subtract 5%2F2 from both sides


-5%2Ax%2B%285%2F2%29%2Ax=6%2F2-5%2F2 Make 3 into a fraction with a denominator of 2


-5%2Ax%2B%285%2F2%29%2Ax=1%2F2 Combine the terms on the right side



%28-10%2F2%29%2Ax%2B%285%2F2%29x=1%2F2 Make -5 into a fraction with a denominator of 2

%28-5%2F2%29%2Ax=1%2F2 Now combine the terms on the left side.


cross%28%282%2F-5%29%28-5%2F2%29%29x=%281%2F2%29%282%2F-5%29 Multiply both sides by 2%2F-5. This will cancel out -5%2F2 and isolate x

So when we multiply 1%2F2 and 2%2F-5 (and simplify) we get



x=-1%2F5 <---------------------------------One answer

Now that we know that x=-1%2F5, lets substitute that in for x to solve for y

-5%28-1%2F5%29%2B1%2Ay=3 Plug in x=-1%2F5 into the 2nd equation

1%2B1%2Ay=3 Multiply

1%2Ay=3-1Subtract 1 from both sides

1%2Ay=2 Combine the terms on the right side

cross%28%281%2F1%29%281%29%29%2Ay=%282%2F1%29%281%2F1%29 Multiply both sides by 1%2F1. This will cancel out 1 on the left side.

y=2%2F1 Multiply the terms on the right side


y=2 Reduce


So this is the other answer


y=2<---------------------------------Other answer


So our solution is

x=-1%2F5 and y=2

which can also look like

(-1%2F5,2)

Notice if we graph the equations (if you need help with graphing, check out this solver)

5%2Ax-2%2Ay=-5
-5%2Ax%2B1%2Ay=3

we get


%0D%0A++drawing%28+500%2C+600%2C+-10.2%2C+10.2%2C+-12%2C+12%2C%0D%0A++++graph%28+500%2C+600%2C+-10.2%2C+10.2%2C+-12%2C+12%2C+%28-5-5%2Ax%29%2F-2%2C+%283--5%2Ax%29%2F1+%29%2C%0D%0A++++blue%28++circle%28+-0.2%2C+2%2C+0.136+%29+%29+%0D%0A++%29%0D%0A++graph of 5%2Ax-2%2Ay=-5 (red) and -5%2Ax%2B1%2Ay=3 (green) (hint: you may have to solve for y to graph these) intersecting at the blue circle.


and we can see that the two equations intersect at (-1%2F5,2). This verifies our answer.


-----------------------------------------------------------------------------------------------
Check:

Plug in (-1%2F5,2) into the system of equations


Let x=-1%2F5 and y=2. Now plug those values into the equation 5%2Ax-2%2Ay=-5

5%2A%28-1%2F5%29-2%2A%282%29=-5 Plug in x=-1%2F5 and y=2


-5%2F5-4=-5 Multiply


-25%2F5=-5 Add


-5=-5 Reduce. Since this equation is true the solution works.


So the solution (-1%2F5,2) satisfies 5%2Ax-2%2Ay=-5



Let x=-1%2F5 and y=2. Now plug those values into the equation -5%2Ax%2B1%2Ay=3

-5%2A%28-1%2F5%29%2B1%2A%282%29=3 Plug in x=-1%2F5 and y=2


5%2F5%2B2=3 Multiply


15%2F5=3 Add


3=3 Reduce. Since this equation is true the solution works.


So the solution (-1%2F5,2) satisfies -5%2Ax%2B1%2Ay=3


Since the solution (-1%2F5,2) satisfies the system of equations


5%2Ax-2%2Ay=-5
-5%2Ax%2B1%2Ay=3


this verifies our answer.



Answer by MathLover1(3376) About Me  (Show Source):
You can put this solution on YOUR website!

Solved by pluggable solver: SOLVE linear system by SUBSTITUTION
Solve:
+system%28+%0D%0A++++5%5Cx+%2B+-2%5Cy+=+-5%2C%0D%0A++++1%5Cx+%2B+-5%5Cy+=+3+%29%0D%0A++We'll use substitution. After moving -2*y to the right, we get:
5%2Ax+=+-5+-+-2%2Ay, or x+=+-5%2F5+-+-2%2Ay%2F5. Substitute that
into another equation:
1%2A%28-5%2F5+-+-2%2Ay%2F5%29+%2B+-5%5Cy+=+3 and simplify: Error: 'Can't call method "invoke_solver" on an undefined value at /home/ichudov/project_locations/algebra.com/templates/Algebra/Solver/PerlSolver.pm line 115. Can't call method "invoke_solver" on an undefined value at /home/ichudov/project_locations/algebra.com/templates/Algebra/Solver/PerlSolver.pm line 115. '. Can't call method "invoke_solver" on an undefined value at /home/ichudov/project_locations/algebra.com/templates/Algebra/Solver/PerlSolver.pm line 115. Can't call method "invoke_solver" on an undefined value at /home/ichudov/project_locations/algebra.com/templates/Algebra/Solver/PerlSolver.pm line 115.
error_location: 101