SOLUTION: One bacterail culture is 18 days older than a second bacterial culture. In 10 days the first culture will be twice the age of the second. Find the present age of the two cultures.
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Question 112631: One bacterail culture is 18 days older than a second bacterial culture. In 10 days the first culture will be twice the age of the second. Find the present age of the two cultures.
x= age of second culture
x+10= age of second culturte in 10 days
x+18= age of first culture
x+18+10= age of first culture in 10 days Answer by scott8148(5895) (Show Source):
