SOLUTION: If 4^x*n^2 = 4^(x+1)*n and x and n are both positive integers, what is the value of n?
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Question 1119251: If 4^x*n^2 = 4^(x+1)*n and x and n are both positive integers, what is the value of n?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
If and x and n are both positive integers, what is the value of n?
divide both sides by n
n =
n =
n =
n = 4
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