SOLUTION: (x-4)^2+8=0
Algebra.Com
Question 1118277: (x-4)^2+8=0
Answer by josgarithmetic(39620) (Show Source): You can put this solution on YOUR website!
What do you want with the equation? Solve?
Two complex solutions
RELATED QUESTIONS
x^4-9x^2+8=0
(answered by edjones)
solve
2^x-4^(1/(2+x))+8^x =... (answered by Vladdroid)
4(2^x)+31(2^x)-8=0 (answered by jim_thompson5910)
x^2-8=0 (answered by funmath)
plot... (answered by adamchapman)
Find the x-intercepts
y=x^2-4x-32
Make y=0 and factor
x^2-4x-32=0
(x-8)(x+4)
(answered by sassycarrie)
(x-4)²+8=0
(x+2)²=3(x+2)
(2x-1)²=(x+1)²
2x(x+4)=(x-3)(x-3)
(answered by josgarithmetic)
x / y
0.0 0.0
0.2 1.8
0.4 3.2
0.6 4.2
0.8 4.8
1.0 5.0
1.2 4.8... (answered by ikleyn)
(x-2)(x-8)=0 (answered by jim_thompson5910)