SOLUTION: The intensity of a television signal varies indirectly as the square of the distance from the transmiter. If the intensity is 27 W/m^2
at a distance of 4.25 km, what is the inten
Question 1114482: The intensity of a television signal varies indirectly as the square of the distance from the transmiter. If the intensity is 27 W/m^2
at a distance of 4.25 km, what is the intensity of a signal at a distance of 5.75? (round answer to two decimal places if needed) Found 4 solutions by josgarithmetic, stanbon, josmiceli, ikleyn:Answer by josgarithmetic(39625) (Show Source): You can put this solution on YOUR website! .... varies indirectly.....
?
Maybe one of these?
Intensity of tv signal varies directly as the square of distance from...
OR
Intensity of tv signal varies inversely as the square of distance from...
? Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website! The intensity of a television signal varies indirectly as the square of the distance from the transmiter. If the intensity is 27 W/m^2
at a distance of 4.25 km, what is the intensity of a signal at a distance of 5.75? (round answer to two decimal places if needed)
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i = k/d^2
Solve for "k"
27 = k/4.25^2
k = 27*4.25^2 = 487.6875
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Equation:
i = 487.6875/5.75^2
i = 14.75
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Cheers,
Stan H.
--------- Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website! W/m2 m
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The intensity is 14.75 W/m2 at
a distance of 5.75 km
check the math