SOLUTION: in an annual candy sale, Jack sold two more boxes than andy. kim sold three times as many as Andy.they sold 37 boxes all together. How many boxes did each person sell?

Question 1113104: in an annual candy sale, Jack sold two more boxes than andy. kim sold three times as many as Andy.they sold 37 boxes all together. How many boxes did each person sell?
Answer by ikleyn(53937) (Show Source): You can put this solution on YOUR website!
.

Jack + Andy  + Kim  = 37


J    + (J+2) + (3J) = 37


5J + 2 = 37


5J = 37 - 2 = 35  ====>  J =  = 7.


Answer.  J = 7,  A = 7+2 = 9,  K = 3*J = 3*7 = 21.


Check.   J + A + K = 7 + 9 + 21 = 37.   ! Correct !

Solved.

=============

Do you need more explanations in addition to this solution ?

RELATED QUESTIONS
These questions are making me confused. 1.The length of a rectangle is one more than... (answered by Alan3354,jorel555)

Kelly, Laura, and Tia sold boxes of cookies for a fundraiser. Kelly sold 15 boxes less... (answered by josmiceli)

John, James, and George sold tickets for the school baseball game. John sold six times... (answered by stanbon)

During a yard sale, Deb earned three times as much money as Andy. Anna made $10 more than (answered by Boreal)

Don runs a charity fruit sale, selling boxes of oranges for $11 and boxes of grapefruit... (answered by doukungfoo)

One calculator costs $3 and a box of pens costs $5. The total amount spent was $960.... (answered by stanbon,nerdybill)

Jim's Market couldn't keep Crunchy Critter Crackers in stock. Jim started with 300 boxes... (answered by josgarithmetic,mananth,ikleyn)

Stickers were sold only in big sheets of 60 stickers each and small sheets of 25 stickers (answered by ikleyn,math_tutor2020,greenestamps)

Jack sold five times as many tickets as Jill, but Jack could not have sold more than 41... (answered by mananth)